70
METHOD OF OBSERVATION AND CALCULATION.
11. Calculation of latitude and longitude of Tok peak.
Elements given.
Latitude N. of Larimo....... 34 8 25 = X
Longitude E. Gr. of Larimo . ... 77 15 56 = L
Azimuth1 from Larimo to Tok peak 37 28 14 = A
Elements sought.
Latitude N. of Tok peak.....= X'
Longitude E. Gr. of Tok peak . . — U
Azimuth from Tok peak to Larimo — B
P. . . .
7
9953315
log cos A
9
•8996378
log dist.
4<
9637170
log \ X
2
8586863
Q ... • •
9
•9980165
log sec X
0
0821459
log tan A 9
8845182
log by L
2
8233669
log sin X
9
7491338
lOg by A
2-
5725007
R. . . .
2-
37987
log sin A
9
7841li
log dist.
4-
96372
log §2 X
9
70025 -
S . . . .
0-
38120
log cot A
0
11548
log 5.2 L
0
19693 -
T. . . .
0
06978
log 5.2 A
0
•26671
For values P, Q, R, S, &c. see table p. 88.
Results.
373-68 = — 0 6 13-68
0-50
5, X
o
= — 0
12
//
2
25
5.2 X
== —
0
50
AX
= — 0
12
2
75
X
= 34
8
25
X'
= 33
56
22
3 Deduced latitude of Tok
by L
= — 0
11
5
[peak.
84
52 L
= +
1
• 57
A L
= — 0
11
4
27
L
= 77
15
56
L'
= 77
4
51
7 Deduced longitude of Tok
by A
= — 0
6
13
[peak.
68
b2A
= —
1
85
= — 0
6
11
83
T.-\-A
217
28
14
B
= 217
= N.37
22
22
2-
2 ■
2
2 E. Deduced azimuth from
Tok peak to Larimo.
Tok peak is situated S. 37° 28' 14" W. of Larimo.
METHOD OF OBSERVATION AND CALCULATION.
11. Calculation of latitude and longitude of Tok peak.
Elements given.
Latitude N. of Larimo....... 34 8 25 = X
Longitude E. Gr. of Larimo . ... 77 15 56 = L
Azimuth1 from Larimo to Tok peak 37 28 14 = A
Elements sought.
Latitude N. of Tok peak.....= X'
Longitude E. Gr. of Tok peak . . — U
Azimuth from Tok peak to Larimo — B
P. . . .
7
9953315
log cos A
9
•8996378
log dist.
4<
9637170
log \ X
2
8586863
Q ... • •
9
•9980165
log sec X
0
0821459
log tan A 9
8845182
log by L
2
8233669
log sin X
9
7491338
lOg by A
2-
5725007
R. . . .
2-
37987
log sin A
9
7841li
log dist.
4-
96372
log §2 X
9
70025 -
S . . . .
0-
38120
log cot A
0
11548
log 5.2 L
0
19693 -
T. . . .
0
06978
log 5.2 A
0
•26671
For values P, Q, R, S, &c. see table p. 88.
Results.
373-68 = — 0 6 13-68
0-50
5, X
o
= — 0
12
//
2
25
5.2 X
== —
0
50
AX
= — 0
12
2
75
X
= 34
8
25
X'
= 33
56
22
3 Deduced latitude of Tok
by L
= — 0
11
5
[peak.
84
52 L
= +
1
• 57
A L
= — 0
11
4
27
L
= 77
15
56
L'
= 77
4
51
7 Deduced longitude of Tok
by A
= — 0
6
13
[peak.
68
b2A
= —
1
85
= — 0
6
11
83
T.-\-A
217
28
14
B
= 217
= N.37
22
22
2-
2 ■
2
2 E. Deduced azimuth from
Tok peak to Larimo.
Tok peak is situated S. 37° 28' 14" W. of Larimo.